I am sorry that the question may be easy.

But I can not find the api in pytorch that normalize a vector into a range, such as into [0,1] or [-1,] which is useful for training

for example:

a_i / sqrt(sum(a_i^2))

I am sorry that the question may be easy.

But I can not find the api in pytorch that normalize a vector into a range, such as into [0,1] or [-1,] which is useful for training

for example:

a_i / sqrt(sum(a_i^2))

It seems that there is no a api, so I use :

```
vec.div_(torch.norm(vec,2))
```

I donâ€™t think there currently is an in-build PyTorch function for what you want.

If you really want a specific function for it, instead of simply doing this yourself, â€śtorchsampleâ€ť: https://github.com/ncullen93/torchsample offers a â€śRangeNormalizeâ€ť function where you can just specify min and max range values (tuples per channel: i.e. ((0,0,0),(1,1,1)) or just floats (0, 1)

1 Like

Wow, That looks very convience for the fresh pytorcher~

For Normalization btw [0,1]

```
x = x/x.sum(0).expand_as(x)
x[torch.isnan(x)]=0 #if an entire column is zero, division by 0 will cause NaNs
```

For Normalization btw [-1,1]

```
x = x/x.sum(0).expand_as(x)
x[torch.isnan(x)]=0 #if an entire column is zero, division by 0 will cause NaNs
x = 2*x - 1
```

x = x/x.sum(0)

I saw you post this in a few places, but it doesnâ€™t look right - why are you dividing by a sum? And youâ€™re not taking into account negative values. i.e. the above code works only under certain conditions, and while it does make the vectorâ€™s max value lesser than 1, it could end up being lesser than 0.0001.

The following code would work correctly for any given 2d vector:

```
# rescale vectors to a desired range
x = torch.tensor([2, -1.0, 5, 6, 7])
if not all(x == 0): # non all-zero vector
# linear rescale to range [0, 1]
x -= x.min() # bring the lower range to 0
x /= x.max() # bring the upper range to 1
x # tensor([0.3750, 0.0000, 0.7500, 0.8750, 1.0000])
# linear rescale to range [-1, 1]
x = 2*x - 1
x # tensor([-0.2500, -1.0000, 0.5000, 0.7500, 1.0000])
```

2 Likes

You are right, mine doesnâ€™t look right. I was using this for a specific use-case. Your snippet is the one to follow. Thank you for pointing this out! Cheers!