I noticed in CosineEmbeddingLoss — PyTorch 2.0 documentation and multiple other functions that 1-D tensors are noted as (N) but pythonically it would be as (N,) while scalar(0-D) would be (N).

It can be mentioned in the torch.tensor page about the form.

ptrblck
September 8, 2023, 3:09pm
2
Wouldn’t scalars be `()`

as also noted in the docs?

```
from torch import tensor
t = tensor(3).detach() # scalar
print(t)
print(t.shape)
t = tensor((3)).detach() # scalar
print(t)
print(t.shape)
t = tensor((3,)).detach()# 1D
print(t)
print(t.shape)
t = torch.tensor(()).detach()# 1D
print(t)
print(t.shape)
```

I ran the following as an example. () would be an empty 1-D vector not a scalar.

ptrblck
September 8, 2023, 4:10pm
4
I see the empty shape for the scalar use case:

```
t = tensor(3) # scalar
print(t)
# tensor(3)
print(t.shape)
# torch.Size([])
```

```
t = torch.tensor(()).detach()# 1D
print(t)
#tensor([])
print(t.shape)
#torch.Size([0])
```

Yes, but , () shows as size [0] - an empty 1-D
but scalars (N) are empty 0-D. This isn’t clear in docs.

```
t = tensor((3)).detach() # scalar
print(t)
#tensor(3)
print(t.shape)
#torch.Size([])
```

See above,
(N) when N is 3 and that is a scalar, not 1-D while the link has (N) as 1-D.