Hi,
I am trying to do multi-task learning with two classification layers from single shared representation.
I believe, having two nn.Linear layers would not differ from having one nn.Linear layer then split,
but it occurs to me they work differently when used with nn.DataParallel.
Please see the code at the bottom.
<class ‘Split’> has one nn.Linear then splits the output.
<class ‘TwoHeads’> has two nn.Linear layers.
What I do in the main code is to compare the outputs of
nn.DataParallel(net)
to
nn.DataParallel(net).module.
For Split the output coincides.
For TwoHeads the output differs.
And the code here.
import torch
import torch.nn as nn
class Split(nn.Module):
def __init__(self):
super(Split, self).__init__()
self.linear = nn.Linear(10, 5)
def forward(self, x):
out = self.linear(x)
out1, out2 = torch.split(out, 3, dim=1)
return out1, out2
class TwoHeads(nn.Module):
def __init__(self):
super(TwoHeads, self).__init__()
self.linear1 = nn.Linear(10, 3)
self.linear2 = nn.Linear(10, 2)
def forward(self, x):
out1 = self.linear1(x)
out2 = self.linear2(x)
return out1, out2
if __name__ == '__main__':
net1 = Split()
net2 = TwoHeads()
for net in [net1, net2]:
net.cuda()
net = nn.DataParallel(net, list(range(4)))
with torch.no_grad():
data = torch.randn(500, 10).cuda()
out1, out2 = net(data)
mod1, mod2 = net.module(data)
print(int(not torch.equal(out1, mod1)), end=' ')
print(int(not torch.equal(out2, mod2)), end=' ')
print((out1 - mod1).abs().max(), (out2 - mod2).abs().max())
For me, the output looks like
0 0 tensor(0., device=‘cuda:0’) tensor(0., device=‘cuda:0’)
0 1 tensor(0., device=‘cuda:0’) tensor(2.3842e-07, device=‘cuda:0’)
My questions are:
- Is it intended?
- If it is because the computation graph uses the same variable twice, shall I always avoid ‘branching’ the computation graph?
- What would be the correct way to do multi-task learning with DataParallel?