Hi ,

I have 2 matrix that have same shape.I want to do element-wise logical_and operation and return a matrix that match the original shape. How to do this?

Thank you for your time and consideration!

Just use

`a * b`

or`torch.mul(a, b)`

Torch.dtype is the data type of torch.tensor, the torch.dtype doesn’t have bool type, similar to bool type is torch.uint8, your can see torch.dtype here. So if do logical_and operation on two tensor, you should expect to get 0/1s numerical values not True/False bool values. And tensor with uint8 type have logical_and operation &, you need change the tensor data type to unint8 first.

```
a = torch.tensor([[0, 1], [0.0, 2.3]])
b = torch.tensor([[1, 1], [0.0, 0.0]])
c = torch.zeros_like(a) # all zero with same shape of a
result = (~torch.eq(a, c)) & (~torch.eq(b, c))
'''
result is a
tensor([[0, 1],
[0, 0]], dtype=torch.uint8)
'''
result.numpy().astype('bool') # change to bool ndarray in numpy
```

1 Like

@zhl515 since pytorch 1.2, there is a dtype torch.bool and associated BoolTensor. The bitwise operators aka numpy (and &, or |, xor ^ and not ~) all work on these as logical operations.