Why use for loop in seq2seq example instead of feed one sequence at once?

I am mention the example here http://pytorch.org/tutorials/intermediate/seq2seq_translation_tutorial.html

The code feed one-by-one token into RNN.

    for ei in range(input_length):
        encoder_output, encoder_hidden = encoder(
            input_variable[ei], encoder_hidden)
        encoder_outputs[ei] = encoder_output[0][0]

However, after reading the doc, I found that RNN can take a sequence in one go (perhaps faster).

So I modified a code a bit.

class EncoderRNN(nn.Module):
    def __init__(self, input_size, hidden_size):
        super(EncoderRNN, self).__init__()
        self.hidden_size = hidden_size

        self.embedding = nn.Embedding(input_size, hidden_size)
        self.gru = nn.GRU(hidden_size, hidden_size)

    def forward(self, input, hidden):
        # embedded = self.embedding(input).view(1, 1, -1)
        embedded = self.embedding(input)
        output = embedded
        output, hidden = self.gru(output, hidden)
        return output, hidden

    def initHidden(self):
        result = Variable(torch.zeros(1, 1, self.hidden_size))
        if use_cuda:
            return result.cuda()
        else:
            return result

Then, in training, I can feed whole sentence without loop


encoder_output, encoder_hidden = encoder(input_variable, encoder_hidden)

Please correct my if I am wrong. I also wonder if the for-loop in example is use on purpose or not.

yes you can , like this :

class Encoder(nn.Module):
    def __init__(self, vocab_size, embedding_size, hidden_size,n_layers=1, dropout=0.3):
        super(Encoder, self).__init__()
        assert hidden_size % 2 == 0
        self.embedding = nn.Embedding(vocab_size, embedding_size)
        self.gru = nn.GRU(embedding_size, hidden_size//2, n_layers,dropout=dropout, bidirectional=True)

    def forward(self, src_batch, hidden=None):
        src_embeddings = self.embedding(src_batch)
        outputs, hidden = self.gru(src_embeddings, hidden)

        return outputs, hidden
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